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Chapter 19 - 19.9

9. We assume scale X is a linear scale in the sense that if its reading is x then it is related to a reading y

on the Kelvin scale by a linear relationship y = mx + b . We determine the constants m and b by solving

the simultaneous equations:

373 . 15= m (

−

53 . 5) + b

273 . 15= m (

−

170) + b

which yield the solutions m =100 / (170

−

53 . 5) = 0 . 858 and b = 419. With these values, we ﬁnd x for

y = 340:

x = y

−

419

0 . 858

−

92 . 1 ◦ X.

= 340