P28_094.PDF

(61 KB) Pobierz

Chapter 28 - 28.94

94. (Second problem of Cluster )

(a) The loop rule (proceeding counterclockwise around the right loop) leads to

E 2 −

i 1 R 1 =0(where

i 1 was assumed downward). This yields i 1 =0 . 060 A(downward).

(b) The loop rule (counterclockwise around the left loop) gives

(+

E 1 )+(+ i 1 R 1 )+(

i 3 R 3 )=0

where i 3 has been assumed leftward. This yields i 3 =0 . 180 A(leftward).

(c) The junction rule tells us that the current through the 12 V battery is 0 . 180 + 0 . 060 = 0 . 240 A

upward.

−