AZIMUTHS
Azimuth:- the bearing of a celestial body from an observer.
P = POLE. Z = ZENITH. X = BODY.
ZP = 000°T PZ = 90° - LAT PX = 90° - DEC (Polar Distance) P = 360° - LHA PZX = AZIMUTH = TRUE BRG ZP = 180°T
PZ = 90° + LAT PX = 90° - DEC (Polar Distance)
P = LHA
PZX = AZIMUTH
TRUE BRG = 180° + AZIMUTH
P = LHA PZX = AZIMUTH
TRUE BRG = 360° - AZIMUTH
P = 360° - LHA
TRUE BRG = 180° - AZIMUTH The Azimuth is calculated using A, B, C Tables or by calculator.
As can be seen from the diagrams the Azimuth is a function of:
· Latitude,
· Declination,
· LHA.
A = Tan Lat Named opposite to Lat except when Hour Angle between 90° and 270°
Tan LHA
B = Tan Dec Always named same as Declination.
Sin LHA
C = A ± B + if A and B are the same names.
- if A and B are different names.
C is named the same as the greater component.
Tan Azimuth = 1
C x Cos Lat
Azimuth is named by C and LHA LHA 0° to 180° Body is to the West of the observer
LHA 180° to 360° Body is to the East of the observer
EXAMPLE 1
If the LHA of a Body = 285°, Observer's Lat = 36°N, Body Dec'n = 15°S. Find the True Bearing of the Body.
EXAMPLE 2
If the LHA of a Body = 48° 15', Observer's Lat = 44° 30'S, Body Dec'n = 23° 20'S. Find the True Bearing of the Body.
EXAMPLE 3
An observer obtains a compass bearing of the sun 110°C at approx 1000 hrs on 17th Dec 95. D.R. Lat 14° 23'S Long 93° 15'W. The Chronometer showed 03:50:23, Error 1m 17s slow. V/l keeping GMT - 6 hours. Calculate the Compass Error.
EXAMPLE 4
Towards the end of the 0000 hrs - 0400 hrs watch on 28th May 1995 an observer,
D.R. 10° 30'S 82° 30'E, obtained bearings of Venus 077°G and star Nunki 235½°G. Chronometer showed 10h 54m 33s, Error 1m 11s fast. Find the Gyro Error.
dariusz.lipinski