p08_022.pdf

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Chapter 8 - 8.22
22. Since time does not directly enter into the energy formulations, we return to Chapter 4 (or Table 2-1 in
Chapter 2) to find the change of height during this t =6sflight.
∆ y = v 0 y t
−
1
2 gt 2
This leads to ∆ y =
−
32 m. Therefore ∆ U = mg ∆ y =
−
318
≈−
320 J.

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