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Chapter 16 - 16.10
10. (a) The problem gives the frequency
f
= 440 Hz, where the SI unit abbreviation Hz stands for Hertz,
which means a cycle-per-second. The angular frequency
ω
is similar to frequency except that
ω
is in radians-per-second. Recalling that 2
π
radians are equivalent to a cycle, we have
ω
=2
πf
2800 rad/s.
(b) In the discussion immediatelyafter Eq. 16-6, the book introduces the velocity amplitude
v
m
=
ωx
m
.
With
x
m
=0
.
00075 m and the above value for
ω
, this expression yields
v
m
=2
.
1m/s.
(c) In the discussion immediately after Eq. 16-7, the book introduces the acceleration amplitude
a
m
=
ω
2
x
m
, which (if the more precise value
ω
= 2765 rad/s is used) yields
a
m
=5
.
7km/s.
≈
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