"In the Example of a fuel cell circuit of FIG. 1, a water capacitor is included. The step-up coil is formed on a conventional torroidal core formed of a compressed ferromagnetic powdered material that will not itself become permanently magnetized, such as the trademarked "Ferramic 06# "Permag" powder as described in Siemens Ferrites Catalog,CG-2000-002-121, (Cleveland, Ohio) No. F626-1205. The core is 1.50 inch in diameter and 0.25 inch in thickness. A primary coil of 200 turns of 24 gauge copper wire is provided and a coil of 600 turns of 36 gauge wire comprises the secondary winding."
Ferramic Torroidal core 1.5inch x 0.25inch
Pri. 200 turns 24 gauge copper wire
Sec. 600 turns 36 gauge wire (I think it is also copper)
Torroidal cap = 1.541pf
Using the Heli. Coil Calculation:
Wire dia. of 36 gauge = 0.005
(http://www.powerstream.com/Wire_Size.htm)
600 turns secondary = arp. 180.722 uh
Self Cap apr .958 pf
Height = about 3 inches (2 turns around core)
Inductor
As the stepped-up pulse enters first inductor (formed from 100 turns of 24 gauge wire 1 inch in diameter), an electromagnetic field is formed around the inductor, voltage is switched off when the pulse ends, and the field collapses and produces another pulse of the same polarity; i.e., another positive pulse is formed where the 50% duty cycle was terminated. Thus, a double pulse frequency is produced; however, in a pulse train of unipolar pulses, there is a brief time when pulses are not present.
100 turns 24 gauge wire 1 inch diameter
24 Gauge = 0.0201 diameter
Using Heli. Coil Calculation:
Inductance 101.667 uH
Self Cap: 1.259 pf
Height = 2 inches
Times 2 because one on each end of the cell.
Res. At 26 volts (only to overcome resistance) at 10 Khz.
(The voltage has nothing to do with the res. Freq. It is just 26 to overcome the resistance of the cell)
At a total of 384 uH a cap size of 0.0065 uf needs to be applied. (10.739 khz)
Find Cap Size of tubes
0.5 inch inner cylinder, 0.75inch outer cylinder Spacing .0625 (1/16 inch)
.5 / 2 * Pie = .7854 inch
and 4 inches long
Plug in surface area and distance for cap formula, I will only use the inner tube as it is the limiting surface area.
Cap size = .000903 uf (0.903 pf)
(Note: Meyer in his patents mentions the inductive capacitance should be twice the size of the water capacitor. In this example that statement is not true, but inductive capacitance is larger than water cap, Inductor1 = 1.259pf, water cap = 0.903pf)
Resonance formula.
Total inductance = 384 uH
Total Capacitance = 0.903 pF
Resonance at 8.546 khz
This has a lot of error(umm guess work in it) because we do not have the actual water, and resistance of the water. However as the dielectric gets smaller the frequency goes up. This guess was biased on a dielectric of 80 for pure water.
The same with the inductor – smaller inductor means a higher frequency.
(Changing only one or the other)
I am fairly sure the Inductance is accurate, The water cap is the large variable right now.
So it is easy to see how 10khz would be resonating – well within error range.
I will run Res. Formula’s for amperage draw at the above noted specs (384uH, 903pF)
26 Volt Primary x 3 on step up transformer
So, 26 * 3 = 78 volt pulse
78 applied in the Res. Circuit so output would be
Amps = about 35 amps
Volts = about 170,000volts
The volts are across the Cap. Only.
Res. At 8536 hz
Shift Frequency to 8551 hz and here is the new voltage and amperage:
Amps = about 1.083
Volts = about 12,000
(Interesting shifting the frequency drops the amperage dramatically, yet still have quite high voltage)
Now, after finding the res frequency we need to add the pulses, can you see why?
5 volts:
Amps = about 2.299
Volts = about 13,000
(Interesting Meyer’s test cell is said to use 5 volts at 2 amps ;-)
Shifting frequency again shows (8551hz)
Amps = about 0.0069
Volts = about 1000
Lets go overboard and use 10,000 volts
(it is said Meyer could dis-associate a gallon of water in a moment with 10,000 volts)
10,000 volts:
Amps = about 4,598 (yes that is a comma)
Volts = about 16,000,000
Again frequency shift (8551hz)
Amps = about 138
Volts = about 130,000
Meyer mentions the diode to allow the collapse of the inductor creating a second pulse – so this points to actually resonating at 20 Khz instead of 10 Khz.
( But, Meyer stated with above details res. Was achieved with 10Khz so there it is.)
It is easy to see how Meyer found the resonant frequency, had a large amperage draw, then adjusted the frequency to drop the amperage. The water only needed, I am guessing, 13,000 volts for dielectric breakdown (as in his test cell on the video: It runs on water – it is said he used 5 volts at 2 amps = 13,000volts. Shift the frequency a little(variable inductor) and watch the amperage go down to milliamps using the high voltage as the key to disassociate the molecules.
This paper seems to address and fit all of what Meyer mentions in his patents – that I have read so far. I hope when I build the actual working model it goes as this paper shows.
Questions that come to mind:
How much water is in between the two tubes?
Is the dielectric constant about 1300 volts per 1/8 inch?
How much water is disassociated at 1300 volts?
How large should the “test vessel” be to accommodate a car?
Is there a way to program for water temp. changes?
Is there a way to program for different water used?
We want the process as automated as possible – turn key and go.
Who wants to do this much math every day before the car would start?
Good luck and best wishes this holiday season.
Warj
czegoniema